(x-3)(2x^2-5x+1)=

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Solution for (x-3)(2x^2-5x+1)= equation: 


Simplifying
(x + -3)(2x2 + -5x + 1) = 0

Reorder the terms:
(-3 + x)(2x2 + -5x + 1) = 0

Reorder the terms:
(-3 + x)(1 + -5x + 2x2) = 0

Multiply (-3 + x) * (1 + -5x + 2x2)
(-3(1 + -5x + 2x2) + x(1 + -5x + 2x2)) = 0
((1 * -3 + -5x * -3 + 2x2 * -3) + x(1 + -5x + 2x2)) = 0
((-3 + 15x + -6x2) + x(1 + -5x + 2x2)) = 0
(-3 + 15x + -6x2 + (1 * x + -5x * x + 2x2 * x)) = 0
(-3 + 15x + -6x2 + (1x + -5x2 + 2x3)) = 0

Reorder the terms:
(-3 + 15x + 1x + -6x2 + -5x2 + 2x3) = 0

Combine like terms: 15x + 1x = 16x
(-3 + 16x + -6x2 + -5x2 + 2x3) = 0

Combine like terms: -6x2 + -5x2 = -11x2
(-3 + 16x + -11x2 + 2x3) = 0

Solving
-3 + 16x + -11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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